Jump to content

zaros_12

Member
  • Posts

    18
  • Joined

  • Last visited

Reputation Activity

  1. zaros_12 liked a post in a topic by Blade in The People's Republic of Kekistan - [S2/OPEN]   
    Good Luck 
  2. Crossfade liked a post in a topic by zaros_12 in Running By The Numbers: How To Get the Most $$$/Hr   
    I can't tell if that's a sex joke or legitimate criticism. lol
  3. PublicEnemy liked a post in a topic by zaros_12 in Running By The Numbers: How To Get the Most $$$/Hr   
    One thing I've noticed is that people in ArmA tend to focus more on combat, loadouts and teamplay than math or the numbers. While it's good to have a solid team/loadout, it never hurts to know your numbers. I'd like to do what I can to contribute, and hopefully shed some light on the math of Atlis Life. 
    I'm going to focus more on helping people do their specifically chosen runs than trying to tell you which is the best. Personally, I've found cocaine the easiest/most consistent, and meth the best money overall (aside from scotch), but that's a story for another thread. 
    In this thread, you'll find tables, screenshots of graphs, equations, etc. I'll try to put the math itself in spoiler boxes, because I know most people would rather just see the results than the logic behind it. 
    Please note that I don't know all of the specific numbers for storage on the various vehicles on Asylum. If you do, please PM me. For now, I'll just have the equations + basic numbers. 
    The equations
    Basically, the equations boil down to this. Our variables are: 
    The first equation we need is: S = Ac + Bd. This line will draw all potential amounts of the items you can have. However, we don't need the same amount of each item. If we need 10 C and 5 D, we'll also plug in the following:
    10C = 5D, or EC = FD.
     
    Crafting Mk-1s, AK-12s, MK14s, Mk18s, and probably some other shit
    For this particular getup, our equations will be as follows (I'll use a box truck + carryall, only holding a pickaxe):
    497 = 2 C + 4 D
    Note that C will be X, and D will be Y when you graph it. Do this, or it won't work. 
    Next, to find the optimal numbers for the amount of each you need, plug in:
    13C = 4D
    Again, this is because you need to find the point at which you can have the most optimal inventory setup with a ratio of 13 cocaine to 4 diamonds. 
    Here's the link to the graph. I couldn't get the stupid ass image to insert.
    Let's say you have two box trucks, so two people. That means, yes, you have 994 total cargo. Let's go back to the first equation.
    997 = 2X + 4Y (or 2C + 4D)
    Let's change it up again. Diamonds now weigh 6, and you need ten of them per item crafted. 
    997 = 2X + 6Y
    13X = 10Y
    Plug them in, find the intercept, and you're good. PS, I use desmos.com for this. Highly recommend. 
    TO REITERATE ONE MORE FUCKING TIME:
    If you are doing Mk-1, AK-12, MK14, or Mk18 runs, assuming you are using a box truck and carryall with a pickaxe, you will want to grab 33 diamonds and 107 cocaine. Easy, right? 
    I've got work and school and all that shit so I'll be adding more to this guide as time goes on, but there's enough here to figure out almost anything you might need to know. Please feel free to PM me if you have any intelligent, stupid ass, or something in-between questions. Thanks for reading.
    PS. If you want to donate, my PayPal email is: [email protected]. This shit takes a lot of time, so I'd appreciate it. If not, I don't really care. 
    Thanks for reading! Lemme know your questions. Thanks
     
    MORE TO BE ADDED SOON
     
     
     
×
×
  • Create New...